网页制作中页面的加密和破解

网页加密, 网页破解

当你在浏览网页时，看到一个很漂亮的特效，你查看源代码时看到的是一队乱码，那多扫兴呀！根据本人的研究，总结出了三种解密方法，与大家分享！！( L! s& L; J( r6 e8 I' n9 }0 h7 }

方法一：
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　　有一种加密的办法是采用javascript的escape()函数，把某些符号、汉字等变成乱码，以达到迷惑人的目的。解密这种代码的办法是采用其反函数加以还原。下面是一个经过加密的例子：$ h  c3 y% Z% Y7 K3 ]6 w6 M
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<HTML>
<SCRIPT LANGUAGE="javascript">3 I9 q, B# v( _9 E% S+ ]; S
var Words ="%3Chtml%3E%3Cbody%20bgcolor%3D%22red%22%3E%3Cp%3E%u8FD9%u662F%u4F8B%u5B50%uFF01%uFF01%uFF1A%uFF09%3C/p%3E%3C/body%3E%3C/html%3E"* J3 S4 D, ]; h4 A; K0 x: Z
var NewWords;* s6 `  e( a9 I
NewWords = unescape(Words);
document.write(NewWords), T3 v9 C! C9 u
</SCRIPT>
<BODY>
</BODY>9 {0 i+ V2 @$ J+ Y" {, ^& u0 K
</HTML>
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　　这种文件最好解密，一看就明白，关键是unescape()函数起了还原源代码的作用。要想看到加密前的代码是什么样子，可以用下面的办法：: W/ X  `" M" }; i/ z# ^1 H. L* a
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<HTML><SCRIPT LANGUAGE="javascript">
var Words ="%3Chtml%3E%3Cbody%20bgcolor%3D%22red%22%3E%3Cp%3E%u8FD9%u662F%u4F8B%u5B50%uFF01%uFF01%uFF1A%uFF09%3C/p%3E%3C/body%3E%3C/html%3E"% I  O7 c, H1 \3 h: e2 I0 r" e  g
var NewWords;2 K# R# H) Q, Y  o& K
NewWords = unescape(Words);4 P  S# K* a( U
NewWords=NewWords.toString();9 V- M' @) j& O$ g, ?
function password(){" m: a- ?# h( i) Y
document.pw.txtpw.value=NewWords;
}$ }' _; U# D$ Z" |$ ]; \) l" b7 {
</SCRIPT>
<BODY>
<form name=pw>
<input type=button onclick="password()" value="解密">; l6 G1 X2 \0 j" e+ }5 |  C
<br>9 n4 }) ~/ s, ^* g. E
<textarea name="txtpw" cols="100" rows="100"></textarea>
</form>
</BODY>
</HTML>
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方法二：
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　　有一个软件叫HTMLEncrypt.exe，它就是把源代码进行加密的软件，这个软件的加密的原理是把字符转换成Unicode代码。下面的例子是一个分帧的页面：
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<html><head><script>1 p" I" d3 w9 v  ^9 Q+ ~( i' o" ?) [0 f. T
function Carbosoft( s ) { var sRet=""; for(j=0; j< s.length; j++ ){ var n= s.charCodeAt(j); if (n>=8364) {n = 128;} sRet += String.fromCharCode( n - 3 ); } return( sRet ); }5 U5 I' ]5 k- r. h  P7 ]6 g
var sJsCmds ="" +
"?kwpoA?khdgA?phwd#kwws0htxly@%Frqwhqw0W|sh%#frqwhqw@%wh{w2kwpo>#fkduvhw@lvr0;;8<04%A?wlwohAZHOFRPH?2wlwohA?phwd#qdph@%JHQHUDWRU%#frqwhqw@%Plfurvriw#IurqwSdjh#613%A?phwd#qdph@%Plfurvriw#Wkhph%#frqwhqw@%qrqh/#ghidxow%A?phwd#qdph@%Plfurvriw#Erughu%#frqwhqw@%qrqh/#ghidxow%A?2khdgA?iudphvhw#erughu@%3%#iudpherughu@%3%#urzv@%-/93%A##?iudph#qdph@%pdlq%#vuf@%xs1kwp%#vfuroolqj@%dxwr%A##?iudph#qdph@%rqolqh%#vuf@%grzq1kwp%#vfuroolqj@%qr%#qruhvl}h#wdujhw@%beodqn%A##?qriudphvA##?erg|A##?sAWklv#sdjh#xvhv#iudphv/#exw#|rxu#eurzvhu#grhvq*w#vxssruw#wkhp1#?2sA##?2erg|A##?2qriudphvA?2iudphvhwA?2kwpoA?irqw#froru@%&33333%A?s#doljq@%fhqwhu%A?vpdooA?irqw#idfh@%Wdkrpd%AWklv#iloh#zdv#hqfu|swhg#xvlqj#dq#xquhjlvwhuhg#yhuvlrq#ri#?d#kuhi@%kwws=22fduer{1wkhgqv1qhw2kwpohqfu|sw1kwp%AKWPO#Hqfu|sw#y413?2dA1?2irqwA?2vpdooA?2sA" +& c& z. ~9 }7 c% W: p
"";
var s= Carbosoft( sJsCmds);  G& N, e+ M: N3 A0 @# k4 V9 v
document.write (s);: o8 Y3 V/ ^- c6 o! z$ w
</script>
</head><body></body></html>
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　　从上面可以看出，浏览器解释这写代码前，进行了还原，从而可以得到破解的方法如下：
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<script>
function Carbosoft( s ) { var sRet=""; for(j=0; j< s.length; j++ ){ var n= s.charCodeAt(j); if (n>=8364) {n = 128;} sRet += String.fromCharCode( n - 3 ); } return( sRet ); }
var sJsCmds ="" +" r" R# Z6 Y+ p8 \( A
"?kwpoA?khdgA?phwd#kwws0htxly@%Frqwhqw0W|sh%#frqwhqw@%wh{w2kwpo>#fkduvhw@lvr0;;8<04%A?wlwohAZHOFRPH?2wlwohA?phwd#qdph@%JHQHUDWRU%#frqwhqw@%Plfurvriw#IurqwSdjh#613%A?phwd#qdph@%Plfurvriw#Wkhph%#frqwhqw@%qrqh/#ghidxow%A?phwd#qdph@%Plfurvriw#Erughu%#frqwhqw@%qrqh/#ghidxow%A?2khdgA?iudphvhw#erughu@%3%#iudpherughu@%3%#urzv@%-/93%A##?iudph#qdph@%pdlq%#vuf@%xs1kwp%#vfuroolqj@%dxwr%A##?iudph#qdph@%rqolqh%#vuf@%grzq1kwp%#vfuroolqj@%qr%#qruhvl}h#wdujhw@%beodqn%A##?qriudphvA##?erg|A##?sAWklv#sdjh#xvhv#iudphv/#exw#|rxu#eurzvhu#grhvq*w#vxssruw#wkhp1#?2sA##?2erg|A##?2qriudphvA?2iudphvhwA?2kwpoA?irqw#froru@%&33333%A?s#doljq@%fhqwhu%A?vpdooA?irqw#idfh@%Wdkrpd%AWklv#iloh#zdv#hqfu|swhg#xvlqj#dq#xquhjlvwhuhg#yhuvlrq#ri#?d#kuhi@%kwws=22fduer{1wkhgqv1qhw2kwpohqfu|sw1kwp%AKWPO#Hqfu|sw#y413?2dA1?2irqwA?2vpdooA?2sA" +
"";
var s= Carbosoft( sJsCmds);- \+ f# H  o. t# ?/ O$ j4 l2 z  T: w
</script>' {* d9 C, i8 [, S% P+ [
<form name=qq>4 v, c' `) O1 i9 _& Q1 T
<textarea name=ww cols=100 rows=10></textarea>( r6 m0 ]6 R( I7 C- P$ r+ R$ G
<input onclick='ww.value=s' type=button value="解密">* P/ W9 Y7 @# D3 ~$ w
</form>. T& c4 F$ b- ]' p4 l6 P8 w, h

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方法三：

　　有一种加密方法是每行单独加密，还原起来比较复杂。看一个加密过的原文：

<HTML>% S& E3 Z1 n2 K: x0 m6 y+ [; \
<BODY>4 x8 A$ r  h/ S
<SCRIPT LANGUAGE="javascript">
function Decode() {% G$ [% e. e# _3 a0 K0 a
d("FrfmnD");d("FruyvDFgwhqjfWnyeseysuEXpydy%whqjf~J~XWghwEXfkjJpgXDFIgwhqjfD");d("FmufyWrffjKuieqdEX?klfulfK$ajuXWwklfulfEXfubfIrfmnGWwryhgufEsx}{~}XD");d("FfqfnuDejFIfqfnuD");d("FIruyvD");d("FxkvaD");d("FIxkvaD");d("FIrfmnD");d("W");return 0;}
</SCRIPT>0 B! \: R' I) F) m9 H& U/ l
<SCRIPT LANGUAGE="javascript">- b& i' w8 z& h% y4 ]3 `
function d (enc) {document.write(codeIt(key,enc));}
var key = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz!\"\ \|#$%&\'()*+,-.\/:;<=>?@[\\]^_\t\`{}~\n";function codeIt (mC, eS) {var wTG, mcH = mC.length / 2, nS = "", dv;for (var x = 0; x < eS.length; x++) { wTG = mC.indexOf(eS.charAt(x));if (wTG > mcH) {dv = wTG - mcH; nS = nS + mC.charAt(48 - dv);}else {dv = mcH - wTG;nS = nS + mC.charAt(48 + dv);}}return nS;}8 O8 t+ j9 j  |- b
</SCRIPT>( {: I" l8 Q- ]
<SCRIPT LANGUAGE="javascript">: E% q: [, z; ]. Q/ g/ `& E, X- H
Decode();
</SCRIPT>. I  x7 f3 M1 D0 K5 _
</BODY>
</HTML>
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　　还原的时候，也必须每行单独解密，用下面的方法可以看到源代码：

<HTML>8 [# Y9 u% _; e5 y
<BODY>/ J) p3 T% w: I1 u6 x* _
<SCRIPT LANGUAGE="javascript">: b- d2 f0 f  t, ~+ L
function Decode() {& G0 r/ n) T% X8 x4 `
d("FrfmnD");d("FruyvDFgwhqjfWnyeseysuEXpydy%whqjf~J~XWghwEXfkjJpgXDFIgwhqjfD");d("FmufyWrffjKuieqdEX?klfulfK$ajuXWwklfulfEXfubfIrfmnGWwryhgufEsx}{~}XD");d("FfqfnuDejFIfqfnuD");d("FIruyvD");d("FxkvaD");d("FIxkvaD");d("FIrfmnD");d("W");return 0;}
</SCRIPT>! t" T% ]5 w4 N8 @: T: l
<SCRIPT LANGUAGE="javascript">8 l7 t8 O. \* D1 ~
function d (enc) {alert(codeIt(key,enc));}, c0 Q% e3 A( _9 M
var key = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz!\"\ \|#$%&\'()*+,-.\/:;<=>?@[\\]^_\t\`{}~\n";function codeIt (mC, eS) {var wTG, mcH = mC.length / 2, nS = "", dv;for (var x = 0; x < eS.length; x++) { wTG = mC.indexOf(eS.charAt(x));if (wTG > mcH) {dv = wTG - mcH; nS = nS + mC.charAt(48 - dv);}else {dv = mcH - wTG;nS = nS + mC.charAt(48 + dv);}}return nS;}: K" c* S/ h# h  x  z  m0 m: x
</SCRIPT>9 z5 Y+ i, H: r% Q
<SCRIPT LANGUAGE="javascript">6 b! S- i4 K2 j: E, `, R% Z
Decode();4 w" u: Y$ S8 d( R/ V0 o
</SCRIPT>) @/ I' }5 e1 q: {9 C) ^* o2 H
</BODY>7 u& y% N5 z& [# ^# m. |8 B, L/ j
</HTML>5 v! y3 z* W3 {0 O7 l

　　哈哈！！:=)是不是很精彩！！

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