实现文件上传的程序源码的PHP源码(页 1) - ASP,PHP,CGI,JSP技术 - 捌玖网络工作室 |网页制作|平面设计|建站交流|代码资料|建站教程|主机域名|asp、php、jsp代码|网站素材

admin 发表于 2007-11-17 08:53

实现文件上传的程序源码的PHP源码

如何实现文件上传 ?[code] u4J&d+ASSx
<HTML>
<HEAD>
<TITLE>文件上传界面</TITLE>
</HEAD>
<BODY><TABLE><CENTER> aK1ldh
<?
if($UploadAction){
$UploadAction=0; 9eOy%]X7{w5?]
$TimeLimit=60;
/*设置超时限制时间默认时间为 30s，设置为0时为不限时 */ +@jFq H2GU
set_time_limit($TimeLimit); D,N"pcX
If(($Upfile != "none")&&
($Upfile != "")) 0X9j.lVb'V
{
$Filepath="d:\web\web\php\test"; //上载文件存放路径
$FileName=$Filepath.$Upfile_name; 1V)`+x4jf{9cvO(_+M
if($Upfile_size <1024) //上载文件大小 %}&eP5R4I6I6|#s
{$FileSize = (string)$Upfile_size . "字节";} ,iQ\9{B$Z
elseif($Upfile_size <(1024 * 1024))
{
$FileSize = number_format((double)($Upfile_size / 1024), 1) . " KB";8I5P7U\Y,Cy
} 4Y;Ps?1F Eu g
else YVK*gc X*K?'wN
{ &Pt6[^vE_:I
$FileSize = number_format((double)($Upfile_size/(1024*1024)),1)."MB";
} kG[,CB3rm0k S7w
if(!file_exists($FileName)) m#yJWk
{ *V?ZM~OF'S[
if(copy($Upfile,$FileName))
{unlink($Upfile);
echo "<br><br>\n";
echo "文件 $Upfile_name 已上载成功！";
echo "<br><br>\n";](V.| Cc
echo "文件位置：$FileName";
echo "<br><br>\n";z)rS4y5zp@x|1w
echo "文件大小：$FileSize";
echo "<br><br>\n";#m'G\]4JltK
}
else 'M7L gv`Q3NU
{echo "文件 $Upfile_name上载失败！"; } s:u Qg;lH
} 2j4ob^,|%p]H
else (|]&xw6dP[:Q%~Z
{echo "文件 $Upfile_name已经存在！"; } +E,y sWp;j6UNhQ
}
else O[^,N5x
{echo "你没有选择任何文件上载！"; } 'av`x{^ V[
set_time_limit(30); //恢复默认超时设置 (h9mc9`B
} gS^6E7rm#t
?>
<FORM ENCTYPE = "multipart/form-data" NAME = "SubmitForm"
ACTION = "default.php" METHOD = "POST">
<INPUT TYPE = "hidden" NAME = "MAX_FILE_SIZE" VALUE ="1000000">
<INPUT TYPE = "hidden" NAME = "UploadAction" VALUE = "1"> 2JfnM2pQ}3wR
<TR><TD><INPUT NAME = "Upfile" TYPE = "file" SIZE = "30"></TD>
</TR><TR><TD><INPUT NAME = "submit" VALUE = "提交" TYPE = "submit">
<INPUT NAME = "reset" VALUE = "重置" TYPE = "reset"></TD> 5c B0Zh gK3sc
</TR></FORM></CENTER></TABLE>
</BODY> ~l9G;S:|pN9z,||
</HTML>[/code]

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实现文件上传的程序源码的PHP源码